Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and put.
get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1.
put(key, value) - Set or insert the value if the key is not already present. When the cache reached its capacity, it should invalidate the least recently used item before inserting a new item.
The cache is initialized with a positive capacity.
Follow up:
Could you do both operations in O(1) time complexity?
Example:
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| LRUCache cache = new LRUCache( 2 /* capacity */ );
cache.put(1, 1);
cache.put(2, 2);
cache.get(1); // returns 1
cache.put(3, 3); // evicts key 2
cache.get(2); // returns -1 (not found)
cache.put(4, 4); // evicts key 1
cache.get(1); // returns -1 (not found)
cache.get(3); // returns 3
cache.get(4); // returns 4
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Solution
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| class LRUCache {
private LinkedList<Node> list = new LinkedList<>();
private Map<Integer, Node> map = new HashMap<>();
private int capacity;
public LRUCache(int capacity) {
this.capacity = capacity;
}
public int get(int key) {
if (map.containsKey(key)) {
Node node = map.get(key);
list.remove(node);
list.addFirst(node);
return node.value;
} else {
return -1;
}
}
public void put(int key, int value) {
Node node = null;
if (map.containsKey(key)) {
node = map.get(key);
list.remove(node);
node.value = value;
} else {
if (list.size() == capacity) {
Node prev = list.pollLast();
map.remove(prev.key);
}
node = new Node(key, value);
}
map.put(key, node);
list.addFirst(node);
}
class Node {
int key, value;
Node(int key, int value) {
this.key = key;
this.value = value;
}
public boolean equals(Node other) {
return this.key == other.key && this.value == other.value;
}
public int hashCode() {
return Objects.hashCode(this.key) + Objects.hashCode(this.value);
}
}
}
/**
* Your LRUCache object will be instantiated and called as such:
* LRUCache obj = new LRUCache(capacity);
* int param_1 = obj.get(key);
* obj.put(key,value);
*/
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