![https://leetcode.com/problems/kth-largest-element-in-an-array/]

Find the kth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, not the kth distinct element.

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Example 1:

Input: [3,2,1,5,6,4] and k = 2
Output: 5

Example 2:

Input: [3,2,3,1,2,4,5,5,6] and k = 4
Output: 4

Note:
You may assume k is always valid, 1 ≤ k ≤ array's length.
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class Solution {
    public int findKthLargest(int[] nums, int k) {
        MinPQ pq = new MinPQ(k);
        
        for (int a: nums) {
            pq.add(a);
        }
        
        return pq.min();
    }
    
    
    static class MinPQ {
        final int[] pq;
        int n = 0;
        
        MinPQ(int size) {
            this.pq = new int[size + 1];
        }
        
        int min() {
            return pq[1];
        }
        
        void add(int i) {
            if (n < pq.length - 1) {
                pq[++n] = i;
                swim(n);
            } else {
                if (i > pq[1]) {
                    pq[1] = i;
                    sink(1);
                }
            }
        }
        
        void sink(int i) {
            int left = 2 * i;
            int right = 2 * i + 1;
            
            int smallest = i;
            
            if (left < pq.length && pq[left] < pq[i]) {
                smallest = left;
            }
            
            if (right < pq.length && pq[right] < pq[smallest]) {
                smallest = right;
            }
            if (smallest != i) {
                swap(i, smallest);
                sink(smallest);
            }
        }
        
        void swim(int i) {
            int j = i / 2;
            if (j > 0 && pq[i] < pq[j]) {
                swap(i, j);
                swim(j);
            }
        }
        
        void swap(int i, int j) {
            int t = pq[i];
            pq[i] = pq[j];
            pq[j] = t;
        }
    }
}

Solution 2

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class Solution {
    public int findKthLargest(int[] nums, int k) {
        int n = nums.length;
        sort(nums, 0, n - 1);
        return nums[n - k];
    }
    
    void sort(int[] nums, int lo, int hi) {
        if (lo >= hi) return;
        int j = partition(nums, lo, hi);
        sort(nums, lo, j - 1);
        sort(nums, j + 1, hi);
    }

    int partition(int[] nums, int lo, int hi) {
        int i = lo;
        int j = hi + 1;
        
        while (true) {
            while (nums[++i] < nums[lo]) {
                if (i == hi) break;
            }
            
            while (nums[lo] < nums[--j]) {
                if (j == lo) break;
            }
            
            if (i < j) {
              swap(nums, i, j);
            } else {
                break;
            }
        }
        
        swap(nums, lo, j);
        return j;
    }
    
    void swap(int[] nums, int i, int j) {
        int tmp = nums[i];
        nums[i] = nums[j];
        nums[j] = tmp; 
    }
}

Solution 3

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class Solution {
    public int findKthLargest(int[] nums, int k) {
        PriorityQueue<Integer> pq = new PriorityQueue<Integer>();
        
        for (int value: nums) {
            pq.add(value);
            if (pq.size() == k + 1) {
                pq.poll();
            }
            // System.out.println(pq);
        }
        
        return pq.peek();
    }
}

Solution - Quick Select

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class Solution {
    public int findKthLargest(int[] nums, int k) {
        int n = nums.length;
        int lo = 0;
        int hi = n - 1;
        while (lo < hi) {
            int j = partition(nums, lo, hi);
            if (j < n - k) {
                lo = j + 1;
            } else if (n - k < j) {
                hi = j - 1;
            } else {
                return nums[n - k];
            }
        }
        return nums[n - k];
    }
    
    int partition(int[] nums, int lo, int hi) {
        int i = lo;
        int j = hi + 1;
        
        while (true) {
            while (nums[++i] < nums[lo]) {
                if (i == hi) break;
            }
            
            while (nums[lo] < nums[--j]) {
                if (j == lo) break;
            }
            
            if (i < j) {
              swap(nums, i, j);
            } else {
                break;
            }
        }
        
        swap(nums, lo, j);
        return j;
    }
    
    void swap(int[] nums, int i, int j) {
        int tmp = nums[i];
        nums[i] = nums[j];
        nums[j] = tmp; 
    }
}

Solution 2022-01-24

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class Solution {
    public int findKthLargest(int[] nums, int k) {
        int n = nums.length;
        int lo = 0;
        int hi = n - 1;
        k = n - k;
        while (lo < hi) {
            int m = partition(nums, lo, hi);
            if (m > k) {
                hi = m - 1;
            } else if (m < k) {
                lo = m + 1;
            } else {
                return nums[m];
            }
        }
        
        return nums[lo];
    }
    int partition(int[] nums, int lo, int hi) {
        int swapIndex = lo;
        while (lo < hi) {
            while (lo < hi && nums[hi] >= nums[swapIndex]) {
                hi--;
            }
            while (lo < hi && nums[lo] <= nums[swapIndex]) {
                lo++;
            }
            swap(nums, lo, hi);
        }
        swap(nums, lo, swapIndex);
        return lo;
    }
    
    void swap(int[] nums, int i, int j) {
        int t = nums[i];
        nums[i] = nums[j];
        nums[j] = t;
    }
}