1827. Minimum Operations to Make the Array Increasing

You are given an integer array nums (0-indexed). In one operation, you can choose an element of the array and increment it by 1.

  • For example, if nums = [1,2,3], you can choose to increment nums[1] to make nums = [1,3,3].

Return the minimum number of operations needed to make nums strictly increasing.

An array nums is strictly increasing if nums[i] < nums[i+1] for all 0 <= i < nums.length - 1. An array of length 1 is trivially strictly increasing.

1
2
3
4
5
6
7
8
Example 1:

Input: nums = [1,1,1]
Output: 3
Explanation: You can do the following operations:
1) Increment nums[2], so nums becomes [1,1,2].
2) Increment nums[1], so nums becomes [1,2,2].
3) Increment nums[2], so nums becomes [1,2,3].
1
2
3
4
Example 2:

Input: nums = [1,5,2,4,1]
Output: 14
1
2
3
4
Example 3:

Input: nums = [8]
Output: 0

Constraints:

  • 1 <= nums.length <= 5000
  • 1 <= nums[i] <= 104

Solution

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
class Solution {
    // nums = [1,5,2,4,1]
    // nums = [1,5,6,4,1]
    public int minOperations(int[] nums) {
        if (nums.length == 1) {
            return 0;
        }
        int count = 0;
        for (int i = 1; i < nums.length; i++) {
            if (nums[i - 1] >= nums[i]) {
                int diff = nums[i - 1] - nums[i]  + 1;
                count = count + diff;
                nums[i] = nums[i] + diff;
            }
        }
        return count;
    }
}