1827. Minimum Operations to Make the Array Increasing
You are given an integer array nums (0-indexed). In one operation, you can choose an element of the array and increment it by 1.
- For example, if nums = [1,2,3], you can choose to increment nums[1] to make nums = [1,3,3].
Return the minimum number of operations needed to make nums strictly increasing.
An array nums is strictly increasing if nums[i] < nums[i+1] for all 0 <= i < nums.length - 1. An array of length 1 is trivially strictly increasing.
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| Example 1:
Input: nums = [1,1,1]
Output: 3
Explanation: You can do the following operations:
1) Increment nums[2], so nums becomes [1,1,2].
2) Increment nums[1], so nums becomes [1,2,2].
3) Increment nums[2], so nums becomes [1,2,3].
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| Example 2:
Input: nums = [1,5,2,4,1]
Output: 14
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| Example 3:
Input: nums = [8]
Output: 0
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Constraints:
- 1 <= nums.length <= 5000
- 1 <= nums[i] <= 104
Solution#
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| class Solution {
// nums = [1,5,2,4,1]
// nums = [1,5,6,4,1]
public int minOperations(int[] nums) {
if (nums.length == 1) {
return 0;
}
int count = 0;
for (int i = 1; i < nums.length; i++) {
if (nums[i - 1] >= nums[i]) {
int diff = nums[i - 1] - nums[i] + 1;
count = count + diff;
nums[i] = nums[i] + diff;
}
}
return count;
}
}
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