1455. Check If a Word Occurs As a Prefix of Any Word in a Sentence
Given a sentence that consists of some words separated by a single space, and a searchWord.
You have to check if searchWord is a prefix of any word in sentence.
Return the index of the word in sentence where searchWord is a prefix of this word (1-indexed).
If searchWord is a prefix of more than one word, return the index of the first word (minimum index). If there is no such word return -1.
A prefix of a string S is any leading contiguous substring of S.
1
2
3
4
5
| Example 1:
Input: sentence = "i love eating burger", searchWord = "burg"
Output: 4
Explanation: "burg" is prefix of "burger" which is the 4th word in the sentence.
|
1
2
3
4
5
| Example 2:
Input: sentence = "this problem is an easy problem", searchWord = "pro"
Output: 2
Explanation: "pro" is prefix of "problem" which is the 2nd and the 6th word in the sentence, but we return 2 as it's the minimal index.
|
1
2
3
4
5
| Example 3:
Input: sentence = "i am tired", searchWord = "you"
Output: -1
Explanation: "you" is not a prefix of any word in the sentence.
|
1
2
3
4
| Example 4:
Input: sentence = "i use triple pillow", searchWord = "pill"
Output: 4
|
1
2
3
4
| Example 5:
Input: sentence = "hello from the other side", searchWord = "they"
Output: -1
|
Constraints:
- 1 <= sentence.length <= 100
- 1 <= searchWord.length <= 10
- sentence consists of lowercase English letters and spaces.
- searchWord consists of lowercase English letters.
Solution#
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
| class Solution {
public int isPrefixOfWord(String sentence, String searchWord) {
int wordsCount = 0;
for (int i = 0; i < sentence.length(); i++) {
if (i == 0 || sentence.charAt(i - 1) == ' ') {
wordsCount++;
int j = 0;
while (j < searchWord.length()
&& sentence.charAt(i) == searchWord.charAt(j)) {
i++;
j++;
}
if (j == searchWord.length()) {
return wordsCount;
}
}
}
return -1;
}
public int isPrefixOfWord2(String sentence, String searchWord) {
int wordsCount = 0;
int j = 0;
boolean start = true;
for (int i = 0; i < sentence.length(); i++) {
char c = sentence.charAt(i);
if (c == ' ') {
wordsCount++;
j = 0;
start = true;
} else {
if (start && c == searchWord.charAt(j)) {
j++;
} else {
start = false;
}
if (j == searchWord.length()) {
return wordsCount + 1;
}
}
}
return -1;
}
}
|