19. Remove Nth Node From End of List
Given the head of a linked list, remove the nth node from the end of the list and return its head.
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| Example 1:
Input: head = [1,2,3,4,5], n = 2
Output: [1,2,3,5]
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| Example 2:
Input: head = [1], n = 1
Output: []
Example 3:
Input: head = [1,2], n = 1
Output: [1]
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Constraints:
- The number of nodes in the list is sz.
- 1 <= sz <= 30
- 0 <= Node.val <= 100
- 1 <= n <= sz
Solution#
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| /**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode() {}
* ListNode(int val) { this.val = val; }
* ListNode(int val, ListNode next) { this.val = val; this.next = next; }
* }
*/
class Solution {
public ListNode removeNthFromEnd(ListNode head, int n) {
ListNode dummy = new ListNode(0);
dummy.next= head;
ListNode walker = dummy;
ListNode runner = dummy;
for (int i = 0; i < n + 1; i++) {
runner = runner.next;
}
while (runner != null) {
walker = walker.next;
runner = runner.next;
}
walker.next = walker.next.next;
return dummy.next;
}
}
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