67. Add Binary
Given two binary strings a and b, return their sum as a binary string.
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| Example 1:
Input: a = "11", b = "1"
Output: "100"
Example 2:
Input: a = "1010", b = "1011"
Output: "10101"
|
Constraints:
- 1 <= a.length, b.length <= 104
- a and b consist only of ‘0’ or ‘1’ characters.
- Each string does not contain leading zeros except for the zero itself.
Solution#
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| class Solution {
public String addBinary(String a, String b) {
int i = a.length() - 1;
int j = b.length() - 1;
int carry = 0;
StringBuilder sb = new StringBuilder();
while (i >= 0 || j >= 0) {
int c1 = (i >= 0) ? a.charAt(i) - '0': 0;
int c2 = (j >= 0) ? b.charAt(j) - '0': 0;
int c3 = c1 + c2 + carry;
if (carry > 0) {
carry = 0;
}
if (c3 == 3) {
carry = 1;
sb.insert(0, '1');
} else if (c3 == 2) {
carry = 1;
sb.insert(0, '0');
} else if (c3 == 1) {
sb.insert(0, '1');
} else {
sb.insert(0, '0');
}
i--;
j--;
}
if (carry > 0) {
sb.insert(0, '1');
}
return sb.toString();
}
public String addBinary2(String a, String b) {
Integer i1 = Integer.parseInt(a, 2);
Integer i2 = Integer.parseInt(b, 2);
return Integer.toBinaryString(i1 + i2);
}
}
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