
Given an unsorted array of integers nums, return the length of the longest consecutive elements sequence.
You must write an algorithm that runs in O(n) time.
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| Example 1:
Input: nums = [100,4,200,1,3,2]
Output: 4
Explanation: The longest consecutive elements sequence is [1, 2, 3, 4]. Therefore its length is 4.
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| Example 2:
Input: nums = [0,3,7,2,5,8,4,6,0,1]
Output: 9
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Constraints:
- 0 <= nums.length <= 105
- -10^9 <= nums[i] <= 10^9
DFS Solution#
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| class Solution {
public int longestConsecutive(int[] nums) {
int n = nums.length;
if (n == 0) return 0;
Arrays.sort(nums);
int max = 1;
int currentMax = 1;
for (int i = 1; i < n ; i++) {
if (nums[i] - nums[i - 1] == 0) {
continue;
} else if (nums[i] - nums[i - 1] == 1) {
currentMax++;
max = Math.max(max, currentMax);
} else {
currentMax = 1;
}
}
return max;
}
}
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