
You are given an array prices where prices[i] is the price of a given stock on the ith day.
You want to maximize your profit by choosing a single day to buy one stock and choosing a different day in the future to sell that stock.
Return the maximum profit you can achieve from this transaction. If you cannot achieve any profit, return 0.
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| Example 1:
Input: prices = [7,1,5,3,6,4]
Output: 5
Explanation: Buy on day 2 (price = 1) and sell on day 5 (price = 6), profit = 6-1 = 5.
Note that buying on day 2 and selling on day 1 is not allowed because you must buy before you sell.
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| Example 2:
Input: prices = [7,6,4,3,1]
Output: 0
Explanation: In this case, no transactions are done and the max profit = 0.
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Constraints:
- 1 <= prices.length <= 10^5
- 0 <= prices[i] <= 10^4
Solution#
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| class Solution {
public int maxProfit(int[] prices) {
int minPrice = Integer.MAX_VALUE;
int maxProfit = 0;
for (int price: prices) {
if (price < minPrice) {
minPrice = price;
} else if (price - minPrice > maxProfit) {
maxProfit = price - minPrice;
}
}
return maxProfit;
}
}
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Solution 2021-11-21#
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| class Solution {
public int maxProfit(int[] prices) {
int min = prices[0];
int profit = 0;
for (int i = 0; i < prices.length; i++) {
if (prices[i] < min) {
min = prices[i];
} else if (prices[i] - min > profit) {
profit = prices[i] - min;
}
}
return profit;
}
}
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