48. Rotate Image

You are given an n x n 2D matrix representing an image, rotate the image by 90 degrees (clockwise).

You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation.

ex1

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Example 1:

Input: matrix = [[1,2,3],[4,5,6],[7,8,9]]
Output: [[7,4,1],[8,5,2],[9,6,3]]

ex2

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Example 2:

Input: matrix = [[5,1,9,11],[2,4,8,10],[13,3,6,7],[15,14,12,16]]
Output: [[15,13,2,5],[14,3,4,1],[12,6,8,9],[16,7,10,11]]

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Example 3:

Input: matrix = [[1]]
Output: [[1]]

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Example 4:

Input: matrix = [[1,2],[3,4]]
Output: [[3,1],[4,2]]

Constraints:

matrix.length == n
matrix[i].length == n
1 <= n <= 20
-1000 <= matrix[i][j] <= 1000

Solution BFS (cut inDegree edges)

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class Solution {
    public void rotate(int[][] matrix) {
        
        int n = matrix.length;
        int m = matrix[0].length;
        for (int i = 0; i < n; i++) { // transpose (i,j) -> (j,i)
            for (int j = 0; j < m; j++) {
                if (i > j) {
                    swap(i, j, j, i, matrix);
                }
            }
        }
        
        for (int i = 0; i < n; i++) { // reflect left -> right
            for (int j = 0; j < m / 2; j++) {
                swap(i, j, i, m - j - 1, matrix);
            }
        }
    }
    
    void swap(int i1, int j1, int i2, int j2, int[][] matrix) {
        int t = matrix[i1][j1];
        matrix[i1][j1] = matrix[i2][j2];
        matrix[i2][j2] = t;
    }
}

Solution BFS (cut inDegree edges)#

Solution BFS (cut inDegree edges)