Given a binary array, find the maximum number of consecutive 1s in this array.

Example 1:

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Input: [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s.
    The maximum number of consecutive 1s is 3.

Note:

  • The input array will only contain 0 and 1.
  • The length of input array is a positive integer and will not exceed 10,000

Solution:

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class Solution {
    public int findMaxConsecutiveOnes(int[] nums) {
        int sum = 0;
        int ans = 0;
        for (int i = 0; i < nums.length; i++) {
            if (nums[i] == 1) {
                sum++;
            } else {
                sum = 0;
            }
            ans = Math.max(ans, sum);
        }
        return ans;
    }
}